\(\int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx\) [2389]

Optimal result

Integrand size = 26, antiderivative size = 165 \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\frac {9568559 \sqrt {1-2 x} \sqrt {3+5 x}}{12800000}+\frac {869869 (1-2 x)^{3/2} \sqrt {3+5 x}}{3840000}+\frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {105254149 \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{12800000 \sqrt {10}} \]

[Out]

-193/2000*(1-2*x)^(7/2)*(3+5*x)^(3/2)-1/20*(1-2*x)^(7/2)*(2+3*x)*(3+5*x)^(3/2)[phone]/128000000*arcsin(1/11
*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)+869869/3840000*(1-2*x)^(3/2)*(3+5*x)^(1/2)+79079/960000*(1-2*x)^(5/2)*(3+5*x
)^(1/2)-7189/32000*(1-2*x)^(7/2)*(3+5*x)^(1/2)+9568559/12800000*(1-2*x)^(1/2)*(3+5*x)^(1/2)

Rubi [A] (verified)

Time = 0.04 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {92, 81, 52, 56, 222} \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\frac {105254149 \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{12800000 \sqrt {10}}-\frac {1}{20} (3 x+2) (5 x+3)^{3/2} (1-2 x)^{7/2}-\frac {193 (5 x+3)^{3/2} (1-2 x)^{7/2}}{2000}-\frac {7189 \sqrt {5 x+3} (1-2 x)^{7/2}}{32000}+\frac {79079 \sqrt {5 x+3} (1-2 x)^{5/2}}{960000}+\frac {869869 \sqrt {5 x+3} (1-2 x)^{3/2}}{3840000}+\frac {9568559 \sqrt {5 x+3} \sqrt {1-2 x}}{12800000} \]

[In]

Int[(1 - 2*x)^(5/2)*(2 + 3*x)^2*Sqrt[3 + 5*x],x]

[Out]

(9568559*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/12800000 + (869869*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x])/3840000 + (79079*(1 -
2*x)^(5/2)*Sqrt[3 + 5*x])/960000 - (7189*(1 - 2*x)^(7/2)*Sqrt[3 + 5*x])/32000 - (193*(1 - 2*x)^(7/2)*(3 + 5*x)
^(3/2))/2000 - ((1 - 2*x)^(7/2)*(2 + 3*x)*(3 + 5*x)^(3/2))/20 + (105254149*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(
12800000*Sqrt[10])

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 56

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 81

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(c + d*x)^
(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 2))), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 92

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[b*(a + b*x
)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(n + p + 3))), x] + Dist[1/(d*f*(n + p + 3)), Int[(c + d*x)^n*(e +
f*x)^p*Simp[a^2*d*f*(n + p + 3) - b*(b*c*e + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(n + p + 4) - b*(d*e*(
n + 2) + c*f*(p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 3, 0]

Rule 222

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps \begin{align*} \text {integral}& = -\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}-\frac {1}{60} \int \left (-186-\frac {579 x}{2}\right ) (1-2 x)^{5/2} \sqrt {3+5 x} \, dx \\ & = -\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {7189 \int (1-2 x)^{5/2} \sqrt {3+5 x} \, dx}{4000} \\ & = -\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {79079 \int \frac {(1-2 x)^{5/2}}{\sqrt {3+5 x}} \, dx}{64000} \\ & = \frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {869869 \int \frac {(1-2 x)^{3/2}}{\sqrt {3+5 x}} \, dx}{384000} \\ & = \frac {869869 (1-2 x)^{3/2} \sqrt {3+5 x}}{3840000}+\frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {9568559 \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx}{2560000} \\ & = \frac {9568559 \sqrt {1-2 x} \sqrt {3+5 x}}{12800000}+\frac {869869 (1-2 x)^{3/2} \sqrt {3+5 x}}{3840000}+\frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {105254149 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{25600000} \\ & = \frac {9568559 \sqrt {1-2 x} \sqrt {3+5 x}}{12800000}+\frac {869869 (1-2 x)^{3/2} \sqrt {3+5 x}}{3840000}+\frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {105254149 \text {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{12800000 \sqrt {5}} \\ & = \frac {9568559 \sqrt {1-2 x} \sqrt {3+5 x}}{12800000}+\frac {869869 (1-2 x)^{3/2} \sqrt {3+5 x}}{3840000}+\frac {79079 (1-2 x)^{5/2} \sqrt {3+5 x}}{960000}-\frac {7189 (1-2 x)^{7/2} \sqrt {3+5 x}}{32000}-\frac {193 (1-2 x)^{7/2} (3+5 x)^{3/2}}{2000}-\frac {1}{20} (1-2 x)^{7/2} (2+3 x) (3+5 x)^{3/2}+\frac {105254149 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{12800000 \sqrt {10}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.24 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.53 \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\frac {10 \sqrt {1-2 x} \left (27911781+354090375 x+328830220 x^2-1017874400 x^3-902544000 x^4+1163520000 x^5+1152000000 x^6\right )-315762447 \sqrt {30+50 x} \arctan \left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )}{384000000 \sqrt {3+5 x}} \]

[In]

Integrate[(1 - 2*x)^(5/2)*(2 + 3*x)^2*Sqrt[3 + 5*x],x]

[Out]

(10*Sqrt[1 - 2*x]*(27911781 + 354090375*x + 328830220*x^2 - 1017874400*x^3 - 902544000*x^4 + 1163520000*x^5 +
1152000000*x^6) - 315762447*Sqrt[30 + 50*x]*ArcTan[Sqrt[5/2 - 5*x]/Sqrt[3 + 5*x]])/(384000000*Sqrt[3 + 5*x])

Maple [A] (verified)

Time = 1.15 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.68

method	result	size
risch	\(-\frac {\left (230400000 x^{5}[phone] x^{4}-237187200 x^{3}-61262560 x^{2}[phone] x +9303927\right ) \left (-1+2 x \right ) \sqrt {3+5 x}\, \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{38400000 \sqrt {-\left (-1+2 x \right ) \left (3+5 x \right )}\, \sqrt {1-2 x}}+\frac {105254149 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{256000000 \sqrt {1-2 x}\, \sqrt {3+5 x}}\)	\(113\)
default	\(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (4608000000 x^{5} \sqrt {-10 x^{2}-x +3}[phone] x^{4} \sqrt {-10 x^{2}-x +3}-4743744000 x^{3} \sqrt {-10 x^{2}-x +3}-1225251200 x^{2} \sqrt {-10 x^{2}-x +3}[phone] \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )[phone] x \sqrt {-10 x^{2}-x +3}[phone] \sqrt {-10 x^{2}-x +3}\right )}{768000000 \sqrt {-10 x^{2}-x +3}}\)	\(138\)

[In]

int((1-2*x)^(5/2)*(2+3*x)^2*(3+5*x)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/38400000*(230400000*x^5+94464000*x^4-237187200*x^3-61262560*x^2+102523580*x+9303927)*(-1+2*x)*(3+5*x)^(1/2)
/(-(-1+2*x)*(3+5*x))^(1/2)*((1-2*x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)[phone]/256000000*10^(1/2)*arcsin(20/11*x+1
/11)*((1-2*x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)/(3+5*x)^(1/2)

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.50 \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\frac {1}{38400000} \, {\left (230400000 \, x^{5} + 94464000 \, x^{4} - 237187200 \, x^{3} - 61262560 \, x^{2} + 102523580 \, x + 9303927\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {105254149}{256000000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \]

[In]

integrate((1-2*x)^(5/2)*(2+3*x)^2*(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

1/38400000*(230400000*x^5 + 94464000*x^4 - 237187200*x^3 - 61262560*x^2 + 102523580*x + 9303927)*sqrt(5*x + 3)
*sqrt(-2*x + 1) - 105254149/256000000*sqrt(10)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(1
0*x^2 + x - 3))

Sympy [F]

\[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\int \left (1 - 2 x\right )^{\frac {5}{2}} \left (3 x + 2\right )^{2} \sqrt {5 x + 3}\, dx \]

[In]

integrate((1-2*x)**(5/2)*(2+3*x)**2*(3+5*x)**(1/2),x)

[Out]

Integral((1 - 2*x)**(5/2)*(3*x + 2)**2*sqrt(5*x + 3), x)

Maxima [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.63 \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=-\frac {3}{5} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x^{3} - \frac {93}{500} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x^{2} + \frac {18251}{40000} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} x + \frac {27893}{480000} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {869869}{640000} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {105254149}{256000000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {869869}{12800000} \, \sqrt {-10 \, x^{2} - x + 3} \]

[In]

integrate((1-2*x)^(5/2)*(2+3*x)^2*(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

-3/5*(-10*x^2 - x + 3)^(3/2)*x^3 - 93/500*(-10*x^2 - x + 3)^(3/2)*x^2 + 18251/40000*(-10*x^2 - x + 3)^(3/2)*x
+ 27893/480000*(-10*x^2 - x + 3)^(3/2) + 869869/640000*sqrt(-10*x^2 - x + 3)*x - 105254149/256000000*sqrt(10)*
arcsin(-20/11*x - 1/11) + 869869/12800000*sqrt(-10*x^2 - x + 3)

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 356 vs. \(2 (120) = 240\).

Time = 0.36 (sec) , antiderivative size = 356, normalized size of antiderivative = 2.16 \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\frac {3}{640000000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (8 \, {\left (4 \, {\left (16 \, {\left (100 \, x - 311\right )} {\left (5 \, x + 3\right )} + 46071\right )} {\left (5 \, x + 3\right )} - 775911\right )} {\left (5 \, x + 3\right )} + 15385695\right )} {\left (5 \, x + 3\right )} - 99422145\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 220189365 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {7}{40000000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (8 \, {\left (12 \, {\left (80 \, x - 203\right )} {\left (5 \, x + 3\right )} + 19073\right )} {\left (5 \, x + 3\right )} - 506185\right )} {\left (5 \, x + 3\right )} + 4031895\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 10392195 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} - \frac {79}{9600000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (8 \, {\left (60 \, x - 119\right )} {\left (5 \, x + 3\right )} + 6163\right )} {\left (5 \, x + 3\right )} - 66189\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 184305 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} - \frac {89}{120000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {1}{250} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {6}{25} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \]

[In]

integrate((1-2*x)^(5/2)*(2+3*x)^2*(3+5*x)^(1/2),x, algorithm="giac")

[Out]

3/640000000*sqrt(5)*(2*(4*(8*(4*(16*(100*x - 311)*(5*x + 3) + 46071)*(5*x + 3) - 775911)*(5*x + 3) + 15385695)
*(5*x + 3) - 99422145)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 220189365*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)))
+ 7/40000000*sqrt(5)*(2*(4*(8*(12*(80*x - 203)*(5*x + 3) + 19073)*(5*x + 3) - 506185)*(5*x + 3) + 4031895)*sqr
t(5*x + 3)*sqrt(-10*x + 5) + 10392195*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) - 79/9600000*sqrt(5)*(2*(4*
(8*(60*x - 119)*(5*x + 3) + 6163)*(5*x + 3) - 66189)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 184305*sqrt(2)*arcsin(1/1
1*sqrt(22)*sqrt(5*x + 3))) - 89/120000*sqrt(5)*(2*(4*(40*x - 59)*(5*x + 3) + 1293)*sqrt(5*x + 3)*sqrt(-10*x +
5) + 4785*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 1/250*sqrt(5)*(2*(20*x - 23)*sqrt(5*x + 3)*sqrt(-10*x
+ 5) - 143*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3))) + 6/25*sqrt(5)*(11*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(
5*x + 3)) + 2*sqrt(5*x + 3)*sqrt(-10*x + 5))

Mupad [F(-1)]

Timed out. \[ \int (1-2 x)^{5/2} (2+3 x)^2 \sqrt {3+5 x} \, dx=\int {\left (1-2\,x\right )}^{5/2}\,{\left (3\,x+2\right )}^2\,\sqrt {5\,x+3} \,d x \]

[In]

int((1 - 2*x)^(5/2)*(3*x + 2)^2*(5*x + 3)^(1/2),x)

[Out]

int((1 - 2*x)^(5/2)*(3*x + 2)^2*(5*x + 3)^(1/2), x)